MCQOPTIONS
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| 1. |
The general transfer function of a digital lag compensator is: |
| A. | \({p_{lag}}\left( z \right) = \frac{{\left( {1 - {p_c}} \right)\left( {z - {z_c}} \right)}}{{\left( {1 - {z_c}} \right)\left( {z - {p_c}} \right)}}{z_c} > {p_c}\) |
| B. | \({p_{lag}}\left( z \right) = \frac{{\left( {1 - {z_c}} \right)\left( {z - {p_c}} \right)}}{{\left( {1 - {p_c}} \right)\left( {z - {z_c}} \right)}}{z_c} < {p_c}\) |
| C. | \({p_{lag}}\left( z \right) = \frac{{\left( {1 - {z_c}} \right)\left( {z - {p_c}} \right)}}{{\left( {1 - {p_c}} \right)\left( {z - {z_c}} \right)}}{z_c} > {p_c}\) |
| D. | \({p_{lag}}\left( z \right) = \frac{{\left( {1 - {p_c}} \right)\left( {z - {z_c}} \right)}}{{\left( {1 - {z_c}} \right)\left( {z - {p_c}} \right)}}{z_c} < {p_c}\) |
| Answer» E. | |