1.

The following grammar is:S → Aa | bAc | Bc | bBaA → dB → d

A. LR(1) and LALR(1)
B. Not LR(1) but LALR(1)
C. LR(1) but not LALR(1)’
D. Neither LR(1) nor LALR(1)
Answer» D. Neither LR(1) nor LALR(1)


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