MCQOPTIONS
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MCQOPTIONS
| 1. |
The foci of the ellipse \(\rm \frac {x^2}{16} + \frac {y^2}{b^2} = 1\) and the hyperbola \(\rm \frac {x^2}{144} - \frac {y^2}{81} = \frac {1}{25}\) coincide. Then the value of b2 is |
| A. | 5 |
| B. | 7 |
| C. | 9 |
| D. | 1 |
| Answer» C. 9 | |