The factorization of \[\mathbf{4}{{\mathbf{a}}^{\mathbf{2}}}-\mathbf{4a}+\mathbf{1}\] is

\[\left( 2a-1 \right)\left( 2a+1 \right)\]

\[\left( 2a-1 \right)\left( 1-2a \right)\]

\[\left( 2a+1 \right)\left( 2a+1 \right)\]

\[\left( 2a- \right)\left( 2a-1 \right)\]

The factorization of \[\mathbf{4}{{\mathbf{a}}^{\mathbf{2}}}-\mathbf{4

1.	The factorization of \[\mathbf{4}{{\mathbf{a}}^{\mathbf{2}}}-\mathbf{4a}+\mathbf{1}\] is
A.	\[\left( 2a-1 \right)\left( 2a+1 \right)\]
B.	\[\left( 2a-1 \right)\left( 1-2a \right)\]
C.	\[\left( 2a+1 \right)\left( 2a+1 \right)\]
D.	\[\left( 2a- \right)\left( 2a-1 \right)\]
Answer» E.

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The factorization of \[\mathbf{4}{{\mathbf{a}}^{\mathbf{2}}}-\mathbf{4a}+\mathbf{1}\] is

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