The expression \(\left[ {\frac{{2x - 7}}{{\left( {x - 2} \right)\left( {x - 3} \right)\left( {x - 4} \right)}} - \frac{1}{{{x^2} - 6x + 8}}} \right] \div \frac{1}{{{x^2} - 5x + 6}}\) where x > 4, is equal to:

The expression \(\left[ {\frac{{2x - 7}}{{\left( {x - 2} \right)\left

1.	The expression \(\left[ {\frac{{2x - 7}}{{\left( {x - 2} \right)\left( {x - 3} \right)\left( {x - 4} \right)}} - \frac{1}{{{x^2} - 6x + 8}}} \right] \div \frac{1}{{{x^2} - 5x + 6}}\) where x > 4, is equal to:
A.	\(\frac{1}{{x - 3}}\)
B.	1
C.	-1
D.	(x – 2) (x – 3)
Answer» C. -1