MCQOPTIONS
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| 1. |
The equation of the tangent at the point (a sec ϕ, b tan ϕ) to the hyperbola \(\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1\) is: |
| A. | \(\frac{x}{a}\sec \phi - \frac{y}{b}\tan \phi = 1\) |
| B. | \(\frac{x}{a}\sec \phi - \frac{y}{b}\tan \phi = 0\) |
| C. | \(\frac{x}{a}\sec \phi + \frac{y}{b}\tan \phi = 0\) |
| D. | \(\frac{x}{{{a^2}}}\sec \phi - \frac{y}{{{b^2}}}\tan \phi = 0\) |
| Answer» B. \(\frac{x}{a}\sec \phi - \frac{y}{b}\tan \phi = 0\) | |