1.

The equation of the line passing through (-4, 3, 1) parallel to the plane and intersecting the line \(\frac{{{\rm{x}} + 1}}{{ - 3}} = \frac{{{\rm{y}} - 3}}{2} = \frac{{{\rm{z}} - 2}}{{ - 1}}\) is: x + 2y – z – 5 = 0

A. \(\frac{{{\rm{x}} - 4}}{2} = \frac{{{\rm{y}} + 3}}{1} = \frac{{{\rm{z}} + 1}}{4}\)
B. \(\frac{{{\rm{x}} + 4}}{1} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{3}\)
C. \(\frac{{{\rm{x}} + 4}}{3} = \frac{{{\rm{y}} - 3}}{{ - 1}} = \frac{{{\rm{z}} - 1}}{1}\)
D. \(\frac{{{\rm{x}} + 4}}{{ - 1}} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{1}\)
Answer» D. \(\frac{{{\rm{x}} + 4}}{{ - 1}} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{1}\)


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