MCQOPTIONS
Saved Bookmarks
| 1. |
The equation of the line passing through (-4, 3, 1) parallel to the plane and intersecting the line \(\frac{{{\rm{x}} + 1}}{{ - 3}} = \frac{{{\rm{y}} - 3}}{2} = \frac{{{\rm{z}} - 2}}{{ - 1}}\) is: x + 2y – z – 5 = 0 |
| A. | \(\frac{{{\rm{x}} - 4}}{2} = \frac{{{\rm{y}} + 3}}{1} = \frac{{{\rm{z}} + 1}}{4}\) |
| B. | \(\frac{{{\rm{x}} + 4}}{1} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{3}\) |
| C. | \(\frac{{{\rm{x}} + 4}}{3} = \frac{{{\rm{y}} - 3}}{{ - 1}} = \frac{{{\rm{z}} - 1}}{1}\) |
| D. | \(\frac{{{\rm{x}} + 4}}{{ - 1}} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{1}\) |
| Answer» D. \(\frac{{{\rm{x}} + 4}}{{ - 1}} = \frac{{{\rm{y}} - 3}}{1} = \frac{{{\rm{z}} - 1}}{1}\) | |