MCQOPTIONS
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| 1. |
The equation of the circle with radius 3 and centre (3, 2) is |
| A. | \({x^2} + {y^2} - 6x - 4y + 4 = 0\) |
| B. | \({x^2} + {y^2} + 6x + 4y + 5 = 0\) |
| C. | \({x^2} + {y^2} + 6x - 4y - 4 = 0\) |
| D. | \({x^2} + {y^2} + 6x + 4y + 10 = 0\) |
| Answer» B. \({x^2} + {y^2} + 6x + 4y + 5 = 0\) | |