1.

The electric field of a uniform plane wave traveling along the negative z-direction is given by the following equation:\({\rm{\vec E}}_{\rm{w}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_0}{{\rm{e}}^{{\rm{jkz}}}}\)This wave is incident upon a receiving antenna placed at the origin and whose radiated electric field towards the incident wave is given by the following equation:\({\rm{\vec E}}_{\rm{a}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_{\rm{I}}}\frac{1}{{\rm{r}}}{\rm{\;}}{{\rm{e}}^{{\rm{-jkr}}}}\)The polarization of the incident wave, the polarization of the antenna and losses due to the polarization mismatch are, respectively,

A. Linear, Circular (clockwise), −5dB
B. Circular (clockwise), Linear, −5dB
C. Circular (clockwise), Linear, −3dB
D. Circular (anti clockwise), Linear, −3dB
Answer» E.


Discussion

No Comment Found