MCQOPTIONS
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| 1. |
The electric field of a plane polarised electromagnetic wave in free space at time t = 0 is given by an expression.\({\rm{E}}\left( {x,y} \right) = 10{\rm{\hat jcos}}\left[ {\left( {6x + 8z} \right)} \right]\)The magnetic field B (x, z, t) is given by (where, c is the velocity of light) |
| A. | \(\frac{1}{c}\left( {6{\rm{\hat k}} - 8\hat i} \right){\rm{cos}}\left[ {\left( {6x + 8z + 10ct} \right)} \right]\) |
| B. | \(\frac{1}{c}\left( {6{\rm{\hat k}} - 8\hat i} \right){\rm{cos}}\left[ {\left( {6x + 8z - 10ct} \right)} \right]\) |
| C. | \(\frac{1}{c}\left( {6{\rm{\hat k}} + 8\hat i} \right){\rm{cos}}\left[ {\left( {6x - 8z + 10ct} \right)} \right]\) |
| D. | \(\frac{1}{c}\left( {6{\rm{\hat k}} + 8\hat i} \right){\rm{cos}}\left[ {\left( {6x + 8z - 10ct} \right)} \right]\) |
| Answer» C. \(\frac{1}{c}\left( {6{\rm{\hat k}} + 8\hat i} \right){\rm{cos}}\left[ {\left( {6x - 8z + 10ct} \right)} \right]\) | |