The diagonals of a parallelogram ABCD intersect at O. If \[{{240}^{o}}\], then \[{{60}^{o}}\] is

• A.  \[{{120}^{o}}\]                              
• B. \[{{180}^{o}}\]
• C.  \[\angle R={{138}^{o}}\]                          
• D.  \[{{90}^{o}}\]