MCQOPTIONS
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| 1. |
The derivative of \(\rm sin ^{-1}\dfrac{2x}{1+x^2}\) w.r.t \(\rm tan ^{-1}\dfrac{2x}{1-x^2}\) is equal to: |
| A. | \(\dfrac{2x}{1-x^2}\) |
| B. | 1 |
| C. | 0 |
| D. | \(\dfrac{x}{1-x}\) |
| Answer» C. 0 | |