The depletion layer width at thermal equilibrium for a one-sided abrupt junction is

Question

TuteeHUB · Accepted Answer

$W_D=\sqrt{\dfrac{2\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{KT}{q}\right)}$

TuteeHUB · Answer

$W_D=\sqrt{\dfrac{\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{2KT}{q}\right)}$

TuteeHUB · Answer

$W_D=\sqrt{\dfrac{2\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{2KT}{q}\right)}$

TuteeHUB · Answer

$W_D=\sqrt{\dfrac{\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{KT}{q}\right)}$

1.	The depletion layer width at thermal equilibrium for a one-sided abrupt junction is
A.	\(W_D=\sqrt{\dfrac{\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{2KT}{q}\right)}\)
B.	\(W_D=\sqrt{\dfrac{2\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{2KT}{q}\right)}\)
C.	\(W_D=\sqrt{\dfrac{2\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{KT}{q}\right)}\)
D.	\(W_D=\sqrt{\dfrac{\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{KT}{q}\right)}\)
Answer» C. \(W_D=\sqrt{\dfrac{2\epsilon_S}{qN}\left(\Psi_{bi}-\dfrac{KT}{q}\right)}\)

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