MCQOPTIONS
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| 1. |
The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T‚ÇÅ = Lowest absolute temperature, and T‚ÇÇ = Highest absolute temperature)$ |
| A. | T‚ÇÅ / (T‚ÇÇ - T‚ÇÅ) |
| B. | (T‚ÇÇ - T‚ÇÅ)/T‚ÇÅ |
| C. | (T‚ÇÅ - T‚ÇÇ)/T‚ÇÅ |
| D. | T‚ÇÇ/ (T‚ÇÇ - T‚ÇÅ) |
| Answer» B. (T‚Äö√á√á - T‚Äö√á√Ö)/T‚Äö√á√Ö | |