The atomic radius of Face Centred Cubic (FCC) crystal is [a = lattice – McqOptions

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1.	The atomic radius of Face Centred Cubic (FCC) crystal is [a = lattice parameter]
A.	\(\frac{{a\sqrt 2 }}{4}\)
B.	\(\frac{{a\sqrt 3 }}{2}\)
C.	\(\frac{{a\sqrt 3 }}{4}\)
D.	\(\frac{{a\sqrt 2 }}{3}\)
Answer» B. \(\frac{{a\sqrt 3 }}{2}\)

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