The area of a triangular field in the shape of a right triangle is \[400\,sq.m.\] where base and altitude are in the ratio \[2:1\]. Find the perimeter.

\[20\left( 3+\sqrt{5} \right)m\]

\[20\left( 3-\sqrt{5} \right)m\]

\[20\left( 3+2\sqrt{5} \right)m\]

The area of a triangular field in the shape of a right triangle is \[4

1.	The area of a triangular field in the shape of a right triangle is \[400\,sq.m.\] where base and altitude are in the ratio \[2:1\]. Find the perimeter.
A.	\[20\left( 3+\sqrt{5} \right)m\]
B.	\[100\,m\]
C.	\[20\left( 3-\sqrt{5} \right)m\]
D.	\[20\left( 3+2\sqrt{5} \right)m\]
Answer» B. \[100\,m\]

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The area of a triangular field in the shape of a right triangle is \[400\,sq.m.\] where base and altitude are in the ratio \[2:1\]. Find the perimeter.

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