MCQOPTIONS
Saved Bookmarks
| 1. |
The angle of elevation of a tower from a distance of 100 mt. from its foot is 30° . Then the height of the tower is: |
| A. | 100 mt./√3 |
| B. | 100 √3 mt. |
| C. | 50√3 |
| D. | 50 mt./√3 |
| Answer» B. 100 √3 mt. | |