1.

Sum of the series \(\frac{1}{2!}+\frac{1}{4!}+ \frac{1}{6!}+ ........\)

A. \(\frac{{{{\left( {e + 1} \right)}^2}}}{{2e}}\)
B. \(\frac{{{{\left( {e - 1} \right)}^2}}}{{2e}}\)
C. \(\frac{{{{\left( {e^2 - 1} \right)}}}}{{2e}}\)
D. \(\frac{{{{{e^2 + 1} }}}}{{2e}}\)
Answer» C. \(\frac{{{{\left( {e^2 - 1} \right)}}}}{{2e}}\)


Discussion

No Comment Found

Related MCQs