$$\sqrt{3}\,\text{cosec}\,{{20}^{o}}-\sec \,{{20}^{o}}=$$ [IIT 1988]

Question

TuteeHUB · Accepted Answer

$$\frac{4\,\sin {{20}^{o}}}{\sin {{40}^{o}}}$$

TuteeHUB · Answer

2

TuteeHUB · Answer

$$\frac{2\,\sin {{20}^{o}}}{\sin {{40}^{o}}}$$

TuteeHUB · Answer

4

\[\sqrt{3}\,\text{cosec}\,{{20}^{o}}-\sec \,{{20}^{o}}=\] [IIT 1988]