1.

Solve for x in 12x2 + 45x = 0

A. x = 0, x = - 45
B. \(x = 0,x = \frac{{ - 15}}{4}\)
C. \(x = 0,\frac{{15}}{4}\)
D. x = 0, x = -12
Answer» B. \(x = 0,x = \frac{{ - 15}}{4}\)


Discussion

No Comment Found