Solve for x: \[\frac{(3x+1)}{16}+\frac{(2x-3)}{7}=\frac{(x+3)}{8}+\fra – McqOptions

MCQOPTIONS

1.	Solve for x: \[\frac{(3x+1)}{16}+\frac{(2x-3)}{7}=\frac{(x+3)}{8}+\frac{(3x-1)}{14}\]
A.	5
B.	\[10\]
C.	\[-14\]
D.	\[12\]
Answer» B. \[10\]

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