MCQOPTIONS
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| 1. |
\({\rm{x}} = \frac{{{\rm{\alpha }}\left( {1 - {{\rm{t}}^2}} \right)}}{{1 + {{\rm{t}}^2}}},{\rm{\;y}} = \frac{{2{\rm{at}}}}{{1 + {{\rm{t}}^2}}}\)What is \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) equal to? |
| A. | \(\frac{{\rm{y}}}{{\rm{x}}}\) |
| B. | \(- \frac{{\rm{y}}}{{\rm{x}}}\) |
| C. | \(\frac{{\rm{x}}}{{\rm{y}}}\) |
| D. | \(- \frac{{\rm{x}}}{{\rm{y}}}\) |
| Answer» E. | |