1.

\({\rm{x}} = \frac{{{\rm{\alpha }}\left( {1 - {{\rm{t}}^2}} \right)}}{{1 + {{\rm{t}}^2}}},{\rm{\;y}} = \frac{{2{\rm{at}}}}{{1 + {{\rm{t}}^2}}}\)What is \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) equal to?

A. \(\frac{{\rm{y}}}{{\rm{x}}}\)
B. \(- \frac{{\rm{y}}}{{\rm{x}}}\)
C. \(\frac{{\rm{x}}}{{\rm{y}}}\)
D. \(- \frac{{\rm{x}}}{{\rm{y}}}\)
Answer» E.


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