${\rm{f}}\left( {\rm{x}} \right) = {\rm{x}}\left| {\rm{x}} \right| - 1{\rm{\;and\;g}}\left( {\rm{x}} \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{{3{\rm{x}}}}{2},{\rm{\;x}} 0}\ {2{\rm{x}},{\rm{\;x}} \le 0} \end{array}} \right.$Where do the curves intersect?

Question

${\rm{f}}\left( {\rm{x}} \right) = {\rm{x}}\left| {\rm{x}} \right| - 1{\rm{\;and\;g}}\left( {\rm{x}} \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{{3{\rm{x}}}}{2},{\rm{\;x}} > 0}\ {2{\rm{x}},{\rm{\;x}} \le 0} \end{array}} \right.$Where do the curves intersect?

TuteeHUB · Accepted Answer

Neither at (2, 3) nor at (-1, -2)

TuteeHUB · Answer

At (2, 3) only

TuteeHUB · Answer

At (-1, -2) only

TuteeHUB · Answer

At (2, 3) and (-1, -2)

1.	\({\rm{f}}\left( {\rm{x}} \right) = {\rm{x}}\left\| {\rm{x}} \right\| - 1{\rm{\;and\;g}}\left( {\rm{x}} \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{{3{\rm{x}}}}{2},{\rm{\;x}} > 0}\\ {2{\rm{x}},{\rm{\;x}} \le 0} \end{array}} \right.\)Where do the curves intersect?
A.	At (2, 3) only
B.	At (-1, -2) only
C.	At (2, 3) and (-1, -2)
D.	Neither at (2, 3) nor at (-1, -2)
Answer» D. Neither at (2, 3) nor at (-1, -2)

\({\rm{f}}\left( {\rm{x}} \right) = {\rm{x}}\left| {\rm{x}} \right| - 1{\rm{\;and\;g}}\left( {\rm{x}} \right) = \left\{ {\begin{array}{*{20}{c}} {\frac{{3{\rm{x}}}}{2},{\rm{\;x}} > 0}\\ {2{\rm{x}},{\rm{\;x}} \le 0} \end{array}} \right.\)Where do the curves intersect?

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