1.

PQRS is a cyclic quadrilateral such that PR is a diameter of the circle. If\[\angle QPR={{67}^{o}}\]and \[\angle SPR={{72}^{o}},\]then \[\angle QRS=\_\_\_\_.\]

A. \[{{41}^{o}}\]
B.        \[{{23}^{o}}\]
C.        \[{{67}^{o}}\]
D.        \[{{18}^{o}}\]
Answer» B.        \[{{23}^{o}}\]


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