PQR is a triangle in which$$\angle $$PQR = $$\mathbf{90}{}^\circ $$ and a perpendicular is drawn from Q to PR which intersects PR at S. If PQ = a, QR = b, PR = c and QS = p, then which one of the following is true?

Question

TuteeHUB · Accepted Answer

None of these

TuteeHUB · Answer

$$cp=ab$$

TuteeHUB · Answer

$$\frac{1}{{{p}^{2}}}=\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}$$

TuteeHUB · Answer

$$\frac{1}{{{p}^{2}}}=\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}-\frac{1}{{{c}^{2}}}$$

TuteeHUB · Answer

both A and B

1.	PQR is a triangle in which\[\angle \]PQR = \[\mathbf{90}{}^\circ \] and a perpendicular is drawn from Q to PR which intersects PR at S. If PQ = a, QR = b, PR = c and QS = p, then which one of the following is true?
A.	\[cp=ab\]
B.	\[\frac{1}{{{p}^{2}}}=\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}\]
C.	\[\frac{1}{{{p}^{2}}}=\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}-\frac{1}{{{c}^{2}}}\]
D.	both A and B
E.	None of these
Answer» E. None of these

PQR is a triangle in which\[\angle \]PQR = \[\mathbf{90}{}^\circ \] and a perpendicular is drawn from Q to PR which intersects PR at S. If PQ = a, QR = b, PR = c and QS = p, then which one of the following is true?

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