PA and PB are two tangents from a point P outside the circle with center O at the point A and B on it. If ∠APB = 130°, then ∠OAB is equal to:

PA and PB are two tangents from a point P outside the circle with cent

1.	PA and PB are two tangents from a point P outside the circle with center O at the point A and B on it. If ∠APB = 130°, then ∠OAB is equal to:
A.	45°
B.	65°
C.	35°
D.	50°
Answer» C. 35°

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PA and PB are two tangents from a point P outside the circle with center O at the point A and B on it. If ∠APB = 130°, then ∠OAB is equal to:

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