MCQOPTIONS
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| 1. |
Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is |
| A. | 2 |
| B. | 5 |
| C. | 7 |
| D. | 8 |
| Answer» E. | |