MCQOPTIONS
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| 1. |
Measurement of power factor for balanced load by two wattmeters for lagging power factor is: |
| A. | \(\tan \phi = \sqrt 3 \left( {\frac{{{W_1} + {W_2}}}{{{W_1} - {W_2}}}} \right)\) |
| B. | \(\tan \phi = - \sqrt 3 \left( {\frac{{{W_1} - {W_2}}}{{{W_1} + {W_2}}}} \right)\) |
| C. | \(\tan \phi = \sqrt 3 \left( {\frac{{{W_1} - {W_2}}}{{{W_1} + {W_2}}}} \right)\) |
| D. | \(\tan \phi = - \sqrt 3 \left( {\frac{{{W_1} + {W_2}}}{{{W_1} - {W_2}}}} \right)\) |
| Answer» D. \(\tan \phi = - \sqrt 3 \left( {\frac{{{W_1} + {W_2}}}{{{W_1} - {W_2}}}} \right)\) | |