\(\mathop \smallint \limits_0^{\frac{\pi }{2}} |\sin x - \cos x|dx\) is equal to

\(2\left( {\sqrt 2 - 1} \right)\)

\(2\left( {\sqrt 2 + 1} \right)\)

\(\mathop \smallint \limits_0^{\frac{\pi }{2}} |\sin x - \cos x|dx\)

1.	\(\mathop \smallint \limits_0^{\frac{\pi }{2}} \|\sin x - \cos x\|dx\) is equal to
A.	0
B.	\(2\left( {\sqrt 2 - 1} \right)\)
C.	\(2\sqrt 2 \)
D.	\(2\left( {\sqrt 2 + 1} \right)\)
Answer» C. \(2\sqrt 2 \)

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\(\mathop \smallint \limits_0^{\frac{\pi }{2}} |\sin x - \cos x|dx\) is equal to

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