Match the following, Column -I Column -II (a) If \[\frac{3}{x+8}=\frac{4}{6-x},\]then \[x\]is ______. (i) 3 (b) if, \[\frac{{{2}^{x-1}}{{.4}^{2x+1}}}{{{8}^{x-1}}}=64,\] (ii) \[-2\] (c) if \[{{4}^{x}}-{{4}^{x}}^{-1}=24\] (iii)\[-2\] (d) \[{{4}^{x+1}}=256,\]then \[x\]is (iv) 1

\[(a)\to (i);(b)\to (ii);(c)\to (iii);(d)\to (iv)\]

\[(a)\to (iii);(b)\to (iv);(c)\to (i);(d)\to (ii)\]

\[(a)\to (i);(b)\to (iv);(c)\to (ii);(d)\to (iii)\]

\[(a)\to (iii);(b)\to (iv);(c)\to (iii);(d)\to (i)\]

Match the following, Column -I Column -II (a) If \[\frac{3}{x+8}=\frac

1.	Match the following, Column -I Column -II (a) If \[\frac{3}{x+8}=\frac{4}{6-x},\]then \[x\]is ______. (i) 3 (b) if, \[\frac{{{2}^{x-1}}{{.4}^{2x+1}}}{{{8}^{x-1}}}=64,\] (ii) \[-2\] (c) if \[{{4}^{x}}-{{4}^{x}}^{-1}=24\] (iii)\[-2\] (d) \[{{4}^{x+1}}=256,\]then \[x\]is (iv) 1
A.	\[(a)\to (i);(b)\to (ii);(c)\to (iii);(d)\to (iv)\]
B.	\[(a)\to (iii);(b)\to (iv);(c)\to (i);(d)\to (ii)\]
C.	\[(a)\to (i);(b)\to (iv);(c)\to (ii);(d)\to (iii)\]
D.	\[(a)\to (iii);(b)\to (iv);(c)\to (iii);(d)\to (i)\]
Answer» E.

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Match the following, Column -I Column -II (a) If \[\frac{3}{x+8}=\frac{4}{6-x},\]then \[x\]is ______. (i) 3 (b) if, \[\frac{{{2}^{x-1}}{{.4}^{2x+1}}}{{{8}^{x-1}}}=64,\] (ii) \[-2\] (c) if \[{{4}^{x}}-{{4}^{x}}^{-1}=24\] (iii)\[-2\] (d) \[{{4}^{x+1}}=256,\]then \[x\]is (iv) 1

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