Match column I with column II and select the correct answer II using the code given below the columns: Column - I Column- II (A) \[xy=b,\] (p) \[\frac{1}{{{x}^{3}}}+\frac{1}{{{y}^{3}}}\] (B) \[\frac{{{a}^{3}}-3ab}{{{b}^{3}}}\] (q) \[\frac{{{a}^{3}}-3a}{{{b}^{3}}}\] (C) \[\frac{{{a}^{3}}-3}{h}\] (r) \[\frac{{{a}^{3}}-3}{{{b}^{2}}}\] (D) \[x=\frac{1}{2}\] (s) \[\begin{align} & x+\overset{1}{\mathop{\_\_\_\_\_\_\_}}\, \\ & 1+\overset{1}{\mathop{\_\_\_\_}}\, \\ & 1+\frac{1}{x} \\ \end{align}\] (E) \[\frac{5}{4}\] (t) \[\frac{4}{5}\] (F) \[\frac{3}{4}\] (u) \[{{2}^{2x-y}}=32\]

• A.  \[{{2}^{x+y}}=16\]\[{{x}^{2}}+{{y}^{2}}\]
• B. \[x-\frac{1}{x-2}=2-\frac{1}{x-2},\]\[(E)\to (t),\,(F)\to (p)\]
• C. \[{{x}^{2}}\]\[{{x}^{a+b+c}}\]
• D. \[{{x}^{abc}}\]\[{{x}^{0}}\]