1.

Let W be the weight per unit length of the conductor, H be the horizontal tension, and l be the span length, then the sag in a freely suspended conductor is determined as:

A. \(\delta = \frac{{W{l}}}{{8H}}\)
B. \(\delta = \frac{{W{l}}}{{4H}}\)
C. \(\delta = \frac{{W{l^2}}}{{8H}}\)
D. \(\delta = \frac{{W{l^2}}}{{4H}}\)
Answer» D. \(\delta = \frac{{W{l^2}}}{{4H}}\)


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