Let ∑un be a series of positive terms. Given that ∑un is convergent and also$\begin{array}{*{20}{c}} {lt}\ {n \to \infty } \end{array}\frac{{{u_{n + 1}}}}{{{u_n}}}$ exists, then the said limit is

Question

Let ∑un be a series of positive terms. Given that ∑un is convergent and also$\begin{array}{*{20}{c}} {lt}\ {n \to \infty } \end{array}\frac{{{u_{n + 1}}}}{{{u_n}}}$ exists, then the said limit is

TuteeHUB · Accepted Answer

May be equal to 1 or less than 1

TuteeHUB · Answer

Necessarily equal to 1

TuteeHUB · Answer

Necessarily greater than 1

TuteeHUB · Answer

Necessarily less than 1

1.	Let ∑un be a series of positive terms. Given that ∑un is convergent and also\(\begin{array}{*{20}{c}} {lt}\\ {n \to \infty } \end{array}\frac{{{u_{n + 1}}}}{{{u_n}}}\) exists, then the said limit is
A.	Necessarily equal to 1
B.	Necessarily greater than 1
C.	Necessarily less than 1
D.	May be equal to 1 or less than 1
Answer» D. May be equal to 1 or less than 1

Let ∑un be a series of positive terms. Given that ∑un is convergent and also\(\begin{array}{*{20}{c}} {lt}\\ {n \to \infty } \end{array}\frac{{{u_{n + 1}}}}{{{u_n}}}\) exists, then the said limit is

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