Let f(x + y) = f(x)f(y) and f(x) = 1 + xg(x)φ(x), where \(\mathop {\lim }\limits_{{\rm{x}} \to 0} {\rm{g}}\left( {\rm{x}} \right) = {\rm{a}}\) and \(\mathop {\lim }\limits_{{\rm{x}} \to 0} \phi \left( {\rm{x}} \right) = {\rm{b}}\) then what is f’(x) equal to?

Let f(x + y) = f(x)f(y) and f(x) = 1 + xg(x)φ(x), where \(\mathop {\l

1.	Let f(x + y) = f(x)f(y) and f(x) = 1 + xg(x)φ(x), where \(\mathop {\lim }\limits_{{\rm{x}} \to 0} {\rm{g}}\left( {\rm{x}} \right) = {\rm{a}}\) and \(\mathop {\lim }\limits_{{\rm{x}} \to 0} \phi \left( {\rm{x}} \right) = {\rm{b}}\) then what is f’(x) equal to?
A.	1 + abf(x)
B.	1 + ab
C.	ab
D.	abf(x)
Answer» E.

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Let f(x + y) = f(x)f(y) and f(x) = 1 + xg(x)φ(x), where \(\mathop {\lim }\limits_{{\rm{x}} \to 0} {\rm{g}}\left( {\rm{x}} \right) = {\rm{a}}\) and \(\mathop {\lim }\limits_{{\rm{x}} \to 0} \phi \left( {\rm{x}} \right) = {\rm{b}}\) then what is f’(x) equal to?

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