1.

\(\left( {\frac{1}{{1{\rm{\;}} + {\rm{\;}}{{\sin }^2}{\rm{\theta }}}}{\rm{}} + {\rm{}}\frac{1}{{1{\rm{\;}} + {\rm{\;\;cose}}{{\rm{c}}^2}{\rm{\theta }}}}} \right){\rm{}} = {\rm{}}?\)

A. 2
B. 1
C. cosec2 θ
D. sin2 θ
Answer» C. cosec2 θ


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