In the given figure, ∠CDB = 50°. ∠DBA = 50°. AD = 4 cm and BC = 4 cm. Then ABCD is a/an _______.

In the given figure, ∠CDB = 50°. ∠DBA = 50°. AD = 4 cm and BC

1.	In the given figure, ∠CDB = 50°. ∠DBA = 50°. AD = 4 cm and BC = 4 cm. Then ABCD is a/an _______.
A.	parallelogram
B.	rhombus
C.	rectangle
D.	Isosceles Trapezium
Answer» E.

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In the given figure, ∠CDB = 50°. ∠DBA = 50°. AD = 4 cm and BC = 4 cm. Then ABCD is a/an _______.

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