MCQOPTIONS
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| 1. |
In the given figure below. PQ is a diameter of the circle whose centre is at O. If \[\angle \mathbf{ROS}=\mathbf{4}{{\mathbf{6}}^{{}^\circ }}\]and OR is a bisector of \[\angle \mathbf{PQR}\], then \[\angle \mathbf{RTS}\] is equal to, |
| A. | \[{{46}^{{}^\circ }}\] |
| B. | \[{{64}^{{}^\circ }}\] |
| C. | \[{{69}^{{}^\circ }}\] |
| D. | \[{{67}^{{}^\circ }}\] |
| Answer» E. | |