1.

In the given figure below. PQ is a diameter of the circle whose centre is at O. If \[\angle \mathbf{ROS}=\mathbf{4}{{\mathbf{6}}^{{}^\circ }}\]and OR is a bisector of \[\angle \mathbf{PQR}\], then \[\angle \mathbf{RTS}\] is equal to,

A.  \[{{46}^{{}^\circ }}\]      
B.  \[{{64}^{{}^\circ }}\]
C.  \[{{69}^{{}^\circ }}\]     
D.  \[{{67}^{{}^\circ }}\]
Answer» E.


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