In the given figure below. O is the centre of the circle. AC and BD intersect at P. If \[\angle \mathbf{AOB}=\mathbf{11}{{\mathbf{0}}^{{}^\circ }}\] and \[\angle \mathbf{DAP}=\mathbf{3}{{\mathbf{0}}^{{}^\circ }}\], then \[\angle \mathbf{APB}\] is equal to

• A. \[{{77}^{{}^\circ }}\]
• B. \[{{80}^{{}^\circ }}\]
• C. \[{{85}^{{}^\circ }}\]
• D. \[{{90}^{{}^\circ }}\]