1.

In the given figure below, ABC is ail isosceles triangle with. The side BA Is produced to D such that \[\mathbf{AB}=\mathbf{AD}\]. If \[\angle ABC={{35}^{{}^\circ }}\], then \[\angle \mathbf{BCD}\] is equal to

A. \[{{45}^{{}^\circ }}\]
B. \[{{90}^{{}^\circ }}\]
C. \[{{30}^{{}^\circ }}\]
D. \[{{60}^{{}^\circ }}\]
Answer» C. \[{{30}^{{}^\circ }}\]


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