MCQOPTIONS
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| 1. |
In the given figure below, ABC is ail isosceles triangle with. The side BA Is produced to D such that \[\mathbf{AB}=\mathbf{AD}\]. If \[\angle ABC={{35}^{{}^\circ }}\], then \[\angle \mathbf{BCD}\] is equal to |
| A. | \[{{45}^{{}^\circ }}\] |
| B. | \[{{90}^{{}^\circ }}\] |
| C. | \[{{30}^{{}^\circ }}\] |
| D. | \[{{60}^{{}^\circ }}\] |
| Answer» C. \[{{30}^{{}^\circ }}\] | |