In the given figure, \[\angle CBP\] is inscribed in a circle. The bisector of \[{{105}^{o}}\] meets BC at D and the circle at E. If EC is joined then\[{{115}^{o}}\]. Find \[{{135}^{o}}\].

• A.  \[\Delta ABC\]                        
• B.  \[\angle BAC\]
• C.  \[\angle ECD={{30}^{o}}\]                       
• D.  \[\angle BAC\]