In the following figure, \[AE\bot BC,\,\,D\] is the mid-point of BC, then \[x\] is equal to

\[\frac{1}{\alpha }\left[ {{b}^{2}}-{{d}^{2}}-\frac{{{a}^{2}}}{4} \right]\]

\[\frac{{{a}^{2}}+{{b}^{2}}+{{d}^{2}}-{{c}^{2}}}{4}\]

In the following figure, \[AE\bot BC,\,\,D\] is the mid-point of BC, t

1.	In the following figure, \[AE\bot BC,\,\,D\] is the mid-point of BC, then \[x\] is equal to
A.	\[\frac{1}{\alpha }\left[ {{b}^{2}}-{{d}^{2}}-\frac{{{a}^{2}}}{4} \right]\]
B.	\[\frac{h+d}{3}\]
C.	\[\frac{c+d-h}{2}\]
D.	\[\frac{{{a}^{2}}+{{b}^{2}}+{{d}^{2}}-{{c}^{2}}}{4}\]
Answer» B. \[\frac{h+d}{3}\]

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In the following figure, \[AE\bot BC,\,\,D\] is the mid-point of BC, then \[x\] is equal to

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