In the figure given below, an isosceles triangle ABC is right angled at B. D is a point inside the triangle ABC. P and Q are the point of the perpendiculars drawn from D on the side AB and AC respectively of \[\Delta \mathbf{ABC}\]. If \[AP=x\] cm, \[\mathbf{AQ=y}\] cm and \[\angle \mathbf{BAD}=\mathbf{1}{{\mathbf{5}}^{{}^\circ }}\]. Then, sin\[{{75}^{{}^\circ }}=\]?

In the figure given below, an isosceles triangle ABC is right angled a

1.	In the figure given below, an isosceles triangle ABC is right angled at B. D is a point inside the triangle ABC. P and Q are the point of the perpendiculars drawn from D on the side AB and AC respectively of \[\Delta \mathbf{ABC}\]. If \[AP=x\] cm, \[\mathbf{AQ=y}\] cm and \[\angle \mathbf{BAD}=\mathbf{1}{{\mathbf{5}}^{{}^\circ }}\]. Then, sin\[{{75}^{{}^\circ }}=\]?
A.	\[\frac{2y}{\sqrt{3x}}\]
B.	\[\frac{x}{2y}\]
C.	\[\frac{\sqrt{3x}}{2y}\]
D.	\[\frac{2x}{\sqrt{3}y}\]
Answer» D. \[\frac{2x}{\sqrt{3}y}\]

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