In the common-base configuration, the collector current is given by:

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TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

${I_C} = \frac{\alpha }{{1 + \alpha }}{I_B} + \frac{1}{{1 - \alpha }}{I_{CBO}}$

TuteeHUB · Answer

${I_C} = \frac{\alpha }{{1 - \alpha }}{I_B} + \frac{1}{{1 + \alpha }}{I_{CBO}}$

TuteeHUB · Answer

${I_C} = \frac{\alpha }{{1 + \alpha }}{I_B} + \frac{1}{{1 + \alpha }}{I_{CBO}}$

TuteeHUB · Answer

${I_C} = \frac{\alpha }{{1 - \alpha }}{I_B} + \frac{1}{{1 - \alpha }}{I_{CBO}}$

1.	In the common-base configuration, the collector current is given by:
A.	\({I_C} = \frac{\alpha }{{1 + \alpha }}{I_B} + \frac{1}{{1 - \alpha }}{I_{CBO}}\)
B.	\({I_C} = \frac{\alpha }{{1 - \alpha }}{I_B} + \frac{1}{{1 + \alpha }}{I_{CBO}}\)
C.	\({I_C} = \frac{\alpha }{{1 + \alpha }}{I_B} + \frac{1}{{1 + \alpha }}{I_{CBO}}\)
D.	\({I_C} = \frac{\alpha }{{1 - \alpha }}{I_B} + \frac{1}{{1 - \alpha }}{I_{CBO}}\)
Answer» E.

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