In the adjoining figure, BD and CD are angle bisectors. Then, which of the following is true?

\[\angle \,x+\angle \,y=\angle \,A+\angle \,D\]

\[\angle \,D=\frac{1}{2}\,\,\angle \,A\]

\[\angle \,D=\frac{\angle \,x+\angle \,y}{2}\]

In the adjoining figure, BD and CD are angle bisectors. Then, which of

1.	In the adjoining figure, BD and CD are angle bisectors. Then, which of the following is true?
A.	\[\angle \,D=\frac{1}{2}\,\,\angle \,A\]
B.	\[\angle \,x+\angle \,y=\angle \,A+\angle \,D\]
C.	\[\angle \,D=\frac{\angle \,x+\angle \,y}{2}\]
D.	All of above
Answer» B. \[\angle \,x+\angle \,y=\angle \,A+\angle \,D\]

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In the adjoining figure, BD and CD are angle bisectors. Then, which of the following is true?

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