MCQOPTIONS
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| 1. |
In the adjoining figure, AP and BP are angle bisectors of \[\angle \mathbf{A}\] and \[\angle B\] which meets At P in the parallelogram ABCD. Then\[\mathbf{2}\angle \mathbf{APB=?}\] |
| A. | \[\angle C+\angle D\] |
| B. | \[\angle A+\angle C\] |
| C. | \[\angle B+\angle D\] |
| D. | \[2\angle C\] |
| Answer» B. \[\angle A+\angle C\] | |