In RLC circuits, the current at resonance is

1.	In RLC circuits, the current at resonance is
A.	maximum is series RLC and minimum in parallel RLC circuit
B.	maximum in parallel circuit and minimum in series circuit
C.	maximum in both circuits
D.	minimum in both circuits
Answer» B. maximum in parallel circuit and minimum in series circuit

Discussion

No Comment Found

Related MCQs

In a series RLC circuit for lower frequency and for higher frequency, power factors are respectively ______________
In a series RLC circuit R = 10 kΩ, L = 0.5 H and C = \(\frac{1}{250}\) μF. Calculate the frequency when the circuit is in a state of resonance.
A series RLC circuit has a resonance frequency of 1 kHz and a quality factor Q = 50. If R and L are doubled and C is kept same, the new Q of the circuit is?
A circuit with a resistor, inductor and capacitor in series is resonant with frequency f Hz. If all the component values are now doubled, then the new resonant frequency will be?
In the circuit given below, the magnitudes of VL and VC are twice that of VK. Calculate the inductance of the coil, given that f = 50.50 Hz.
For the circuit given below, if the frequency of the source is 50 Hz, then a value of to which results in a transient free response is?
A 440 V, 50 HZ AC source supplies a series LCR circuit with a capacitor and a coil. If the coil has 100 mΩ resistance and 15 mH inductance, then at a resonance frequency of 50 Hz, the Q factor of the circuit is?
A 440 V, 50 HZ AC source supplies a series LCR circuit with a capacitor and a coil. If the coil has 100 mΩ resistance and 15 mH inductance, then at a resonance frequency of 50 Hz, what is the value of the capacitor?
At what frequency will the current lead the voltage by 30° in a series circuit with R = 10Ω and C = 25 μF?
Two series resonant filters are shown below. Let the 3 dB bandwidth of filter 1 be B1 and that of filter 2 be B2. The value of \(\frac{B_1}{B_2}\) is ____________

In RLC circuits, the current at resonance is

Discussion

No Comment Found

Related MCQs

Reply to Comment