In ΔABC, P is a point on BC such that BP ∶ PC = 3 ∶ 4 and Q is the midpoint of BP. Then ar(ΔABQ) ∶ ar(ΔABC) is equal to∶

In ΔABC, P is a point on BC such that BP ∶ PC = 3 ∶ 4 and Q is th

1.	In ΔABC, P is a point on BC such that BP ∶ PC = 3 ∶ 4 and Q is the midpoint of BP. Then ar(ΔABQ) ∶ ar(ΔABC) is equal to∶
A.	3 ∶ 8
B.	2 ∶ 7
C.	1 ∶ 4
D.	3 ∶ 14
Answer» E.

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In ΔABC, P is a point on BC such that BP ∶ PC = 3 ∶ 4 and Q is the midpoint of BP. Then ar(ΔABQ) ∶ ar(ΔABC) is equal to∶

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