In ΔABC, P is a point on BC such that BP : PC = 2 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : ar(ΔABC) is equal to:

In ΔABC, P is a point on BC such that BP : PC = 2 : 3 and Q is the mi

1.	In ΔABC, P is a point on BC such that BP : PC = 2 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : ar(ΔABC) is equal to:
A.	1 : 4
B.	2 : 5
C.	1 : 5
D.	2 : 3
Answer» D. 2 : 3

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In ΔABC, P is a point on BC such that BP : PC = 2 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : ar(ΔABC) is equal to:

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