In ΔABC, P is a point on BC such that BP ∶ PC = 1 ∶ 2 and Q is the midpoint of BP. Then, ar(ΔABQ) ∶ ar(ΔABC) is

In ΔABC, P is a point on BC such that BP ∶ PC = 1 ∶ 2 and Q is th

1.	In ΔABC, P is a point on BC such that BP ∶ PC = 1 ∶ 2 and Q is the midpoint of BP. Then, ar(ΔABQ) ∶ ar(ΔABC) is
A.	1 ∶ 5
B.	1 ∶ 3
C.	1 ∶ 4
D.	1 ∶ 6
Answer» E.

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In ΔABC, P is a point on BC such that BP ∶ PC = 1 ∶ 2 and Q is the midpoint of BP. Then, ar(ΔABQ) ∶ ar(ΔABC) is

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