In ΔABC, AD ⊥ BC, then – McqOptions

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1.	In ΔABC, AD ⊥ BC, then
A.	B2 - BD2 = AC2 - CD2
B.	B2 + BD2 = AC2 - CD2
C.	B2 - BD2 = AC2 + CD2
D.	B2 - AC2 = BD2 + CD2
Answer» B. B2 + BD2 = AC2 - CD2

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